Q1: Balance the equation \( \text{Sb} + \text{Cl}_2 \rightarrow \text{SbCl}_3 \)
Answer: \( 3\text{Sb} + 3\text{Cl}_2 \rightarrow 3\text{SbCl}_3 \)
Explanation: To balance the equation, we need three antimony (Sb) atoms and six chlorine (Cl) atoms on the reactant side, which corresponds to three SbCl3 molecules.
Q2: Balance the equation \( \text{GaBr}_3 + \text{Cl}_2 \rightarrow \text{GaCl}_3 + \text{Br}_2 \)
Answer: \( 2\text{GaBr}_3 + 3\text{Cl}_2 \rightarrow 2\text{GaCl}_3 + 3\text{Br}_2 \)
Explanation: To balance this equation, we need two gallium bromide (GaBr3) molecules to provide six bromine atoms, which will yield three bromine molecules (Br2) and two gallium chloride (GaCl3) molecules, which require six chlorine atoms from three Cl2 molecules.